Bangladesh Rural Electrification Board(BREB)
Post: Assistant Programmer
Exam Date: 18.02.2023. Exam Taker: BREB
#include <stdio.h>
int main() {
char str[100], temp;
int i, len = 0;
printf("Enter a string: ");
gets(str);
// Find length manually
while (str[len] != '\0') {
len++;
}
// Reverse the string
for (i = 0; i < len / 2; i++) {
temp = str[i];
str[i] = str[len - i - 1];
str[len - i - 1] = temp;
}
printf("Reversed string: %s\n", str);
return 0;
}
Private IP Ranges and Maximum Hosts for Classes A, B, and C
Class A
IP Range: 10.0.0.0 – 10.255.255.255
Maximum Hosts: 224 – 2 = 16,777,214 hosts per network
Class B
IP Range: 172.16.0.0 – 172.31.255.255
Maximum Hosts: 216 – 2 = 65,534 hosts per network
Class C
IP Range: 192.168.0.0 – 192.168.255.255
Maximum Hosts: 28 – 2 = 254 hosts per network
#include <iostream>
using namespace std;
int main () {
int i=1,j=1,k=1;
cout << ++i || ++j && ++k;
cout << i << j << k;
return 0;
}
Given code:
i = 1, j = 1, k = 1
Expression:
++i || ++j && ++k
Step 1: Operator precedence
&& has higher priority than ||
So expression becomes:
++i || (++j && ++k)
Step 2: Evaluate ++i
++i → i = 2 (true)
Since left side of || is true, right side is not evaluated (short-circuit).
So:
j = 1, k = 1 (unchanged)
Result of expression = 1
Step 3: Output
First cout prints: 1
Second cout prints: i j k = 2 1 1
Final Output:
1
211
int main () {
float p=10.5;
int a=5*p +5.0;
printf ("%d", a);
return 0;
}
Code Analysis:
p = 10.5
a = 5 * p + 5.0
= 5 × 10.5 + 5.0
= 52.5 + 5.0
= 57.5
Now, a is int, so decimal part is truncated:
a = 57
Final Output:
57
7. Write a composition E-commerce in Bangladesh.
