Bangladesh Ordnance Factory
Post: Assistant Programmer and Assistant Maintenance Engineer
Exam Date: 2022, Exam Taker: MIST
Sample Output:
How Many Students? 5
Enter the Elements of the Array: 49 60 7 80 90
Average is: 69
3 Number students got above of the Average
2 number of students got below of the average.
#include <stdio.h>
#include <math.h>
int main() {
int n, i;
printf("How Many Students? ");
scanf("%d", &n);
int a[1000], sum = 0, avg, aboveAvg = 0, belowAvg = 0;
printf("Enter the Elements of the Array: \n");
for (i = 0; i < n; i++) {
scanf("%d", &a[i]);
sum += a[i];
}
avg = sum / n;
for (i = 0; i < n; i++) { if (a[i] > avg)
aboveAvg++;
else if (a[i] < avg)
belowAvg++;
}
printf("\nAverage is %d.\n", avg);
printf("%d students got above the average.\n", aboveAvg);
printf("%d students got below the average.\n", belowAvg);
return 0;
}
Sample I/O:
How Many Students? 5
Enter the Elements of the Array:
50
53
60
49
51
Average is 52.
2 students got above the average.
3 students got below the average.
=== Code Execution Successful ===
i) Network address of this network?
ii) What is the subnet mask of this Network?
iii) How many hosts can cover the network?
- Network Address: 172.3.16.0
- Subnet Mask: 255.255.254.0 or /23
- Hosts per Network: 510
- Broadcast IP Address: 172.3.17.255
- First Valid Host: 172.3.16.1
- Last Valid Host: 172.3.17.254
#include<stdio.h>
int fun(int n) {
if (n == 4)
return n;
else
return 2 * fun(n + 1);
}
int main() {
printf("%d ", fun(2));
return 0;
}
Answer: 16
Explanation:
1. Function fun is called with n = 2
– The if condition n == 4 is false.
– Therefore, it goes to the else branch: return 2 * fun(n + 1);
– This means it will call fun(3).
2. Function fun is called with n = 3
– The if condition n == 4 is false again.
– It goes to the else branch: return 2 * fun(n + 1);
– This means it will call fun(4).
3. Function fun is called with n = 4
– The if condition n == 4 is true this time.
– It returns 4.
4. Returning to the previous call where n = 3
– return 2 * fun(4) becomes return 2 * 4 which is 8.
5. Returning to the first call where n = 2
– return 2 * fun(3) becomes return 2 * 8 which is 16.
Final Output:
The final output of the program will be:
16
This is because the function keeps doubling the returned value until it reaches the base case where n == 4.
