Bangladesh Rural Electrification Board
Post: Assistant Programmer
Exam Date: 21.02.2025, Exam Taker: BREB
1. Write a program to check Armstrong.
#include<stdio.h>
#include<math.h>
int main() {
int num, originalNum, remainder, n = 0;
double result = 0.0;
printf("Enter an integer: ");
scanf("%d", &num);
originalNum = num;
// Count number of digits
while (originalNum != 0) {
originalNum /= 10;
++n;
}
originalNum = num;
// Calculate Armstrong sum
while (originalNum != 0) {
remainder = originalNum % 10;
result += pow(remainder, n);
originalNum /= 10;
}
if ((int)result == num)
printf("%d is an Armstrong number.\n", num);
else
printf("%d is not an Armstrong number.\n", num);
return 0;
}
2(a) Find the output of the following program
int main() {
for (i=0; i<=5; i++) {
continue;
}
printf("%d", i);
return 0;
}
int main() {
for (i=0; i<=5; i++) {
continue;
}
printf("%d", i);
return 0;
}
- The loop starts from i = 0.
- The loop runs while i <= 5.
- The continue statement skips the remaining statements inside the loop body (if any) and moves to the next iteration.
- The loop executes for i = 0, 1, 2, 3, 4, 5.
- After the last iteration, i becomes 6 and the loop condition fails.
Final Output:
6
2(b) Find the output of the following program
int main() {
string str1 = Bangladesh;
string str2;
str1[4] = '\0';
printf("%s", str1);
}
int main() {
string str1 = Bangladesh;
string str2;
str1[4] = '\0';
printf("%s", str1);
}
- The string “Bangladesh” is stored in str1.
- String indexing starts from 0.
- Index positions: B(0) a(1) n(2) g(3) l(4) a(5) d(6) e(7) s(8) h(9).
- str1[4] = ‘\0’ replaces the character at index 4 (l) with the null character.
- In C, ‘\0’ indicates the end of a string.
- So the string becomes “Bang”.
3. Join related query
Assume two tables:
— Student (StudentID, StudentName, DepartmentID)
— Department (DepartmentID, DepartmentName)
-- 1) INNER JOIN
SELECT s.StudentID, s.StudentName, d.DepartmentName
FROM Student s
INNER JOIN Department d
ON s.DepartmentID = d.DepartmentID;
-- 2) LEFT JOIN (LEFT OUTER JOIN)
SELECT s.StudentID, s.StudentName, d.DepartmentName
FROM Student s
LEFT JOIN Department d
ON s.DepartmentID = d.DepartmentID;
-- 3) RIGHT JOIN (RIGHT OUTER JOIN)
SELECT s.StudentID, s.StudentName, d.DepartmentName
FROM Student s
RIGHT JOIN Department d
ON s.DepartmentID = d.DepartmentID;
-- 4) FULL JOIN (FULL OUTER JOIN)
SELECT s.StudentID, s.StudentName, d.DepartmentName
FROM Student s
FULL OUTER JOIN Department d
ON s.DepartmentID = d.DepartmentID;
4. Abbreviations: HTTP, DVD, SMTP
HTTP – HyperText Transfer Protocol
DVD – Digital Versatile Disc
SMTP – Simple Mail Transfer Protocol
5. Check the valid IP address from the following table.
1.1.1.1
67.67.121.121
154.154.121.121
1.1.1.1
67.67.121.121
154.154.121.121
6. Describe the function of DHCP
7. In how many ways can a transaction be completed?
Or 7. In how many propertise of a transaction?
- Paragraph on Three Zero Theory.
- গ্রামীন জীবন যাত্রার মান উন্নয়নে পল্লী বিদ্যুতের ভূমিকা।
- Full Form of: ASEAN, SPARRSO, BERC
- Translation
- ও , এবং এর পার্থক্য,
- এক কথায় প্রকাশ
